f(-2)=3-2^2+5-2+3

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Solution for f(-2)=3-2^2+5-2+3 equation: 



f(-2)=3-2^2+5-2+3

We move all terms to the left:

f(-2)-(3-2^2+5-2+3)=0

We add all the numbers together, and all the variables

f(-2)-5=0

We multiply parentheses

-2f-5=0

We move all terms containing f to the left, all other terms to the right

-2f=5

f=5/-2

f=-2+1/2

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